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Skio, a 2020 Y Combinator alum that was founded by self-described college dropout Kennan Frost, has been acquired by competitor Recharge, the companies announced on Thursday.<\/p>\n
Both Skio and Recharge make products that handle subscription payments for brands.<\/p>\n
While the official press release did not disclose the terms of the deal, Frost (who had previously left the company), posted on X, LinkedIn, and Instagram that his startup walked with $105 million cash and had only raised $8 million from investors. That\u2019s a healthy return by any measure.<\/p>\n
His posts about the deal were reposted by Skio investors Y Combinator and Nicolas Wittenborn, founder of VC firm Adjacent.<\/p>\n
Frost had not been running the company for about two years, according to a LinkedIn post by Skio\u2019s current CEO, Aidan Thibodeaux, who began as the startup\u2019s first COO. When he took over, he described a grind that involved no spend on marketing, ads, or a sales team. Instead, they focused spending exclusively on building the product. He and the founding CTO, Andrew Chen, made every sales call themselves, he wrote.<\/p>\n
Frost\u2019s story is even more stirring. In his Instagram post, he wrote that he solo-founded the startup after having a panic attack that caused him to leave his job as an engineer at Pinterest. COVID shut the world down two weeks later.<\/p>\n
Frost got into YC and says in another post that he \u201ccompletely failed during the batch,\u201d until he pivoted to this subscription idea. In three years, he got the company to $10 million in ARR and, he says, profitable. Then another \u201cteam came together and turned this early traction into a real company,\u201d he credits.<\/p>\n
Techcrunch event<\/p>\n
\n\t\t\t\t\t\t\t\t\tSan Francisco, CA<\/span> His YC advisor, Gustaf Alstr\u00f6mer, confirmed the terms of the sale on X. Alstr\u00f6mer described how the founder struggled during his time at the accelerator but never gave up.<\/p>\n
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\n\t\t\t\t\t\t\t\t\t\t\t\t\tOctober 13-15, 2026<\/span>\n\t\t\t\t\t\t\t<\/p>\n<\/p><\/div>\n<\/p><\/div>\n<\/div>\n